In cases with a tie in the sales column, such as Alan, Carl, and Esther having sales of 150 (though in different years), the same rank of ‘3’ is assigned to all three rows. We can observe that there are gaps in the assigned ranks. So first, we sort the data in ascending order of the number of sales, assign a rank to each row, and display the data. Also, there is an ORDER BY clause which specifies to order the data in ascending order of sales column. The query says to display the column employee, year, sales, and RANK() with a RANK column titled as sales_rank. Now we can rank the rows and get the output. The table holds data on sales by each employee per year. For reference, we can consider the EMPLOYEE table. With the above-given syntax, let us write a query with the RANK function. Let us explore this in detail with an example. This makes the gaps or holes in the rankings. This function considers the same values in a column as ties and skips assigning consecutive ranks instead of giving the same rank to the row with a tie. So as discussed, the RANK() function returns ranks of rows under a specific partition which is neatly ordered in ascending or descending order. Once arranged in an order, we can only identify whether there are ties in the values. Ordering the results is mandatory to assign the ranks to rows. PARTITION BY – this part of the query will order the result set in ascending or descending order.RANK() over ( … ) rank_column_name – this part of the query will return the result of RANK() function and the output will hold the column as rank_column_name.SELECT – In the SELECT query we utilize the RANK() function to obtain the desired ranks of rows as output from the table being considered.The syntax for the RANK() function is as follows: SELECT column_name
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